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3/4x^2=6
We move all terms to the left:
3/4x^2-(6)=0
Domain of the equation: 4x^2!=0We multiply all the terms by the denominator
x^2!=0/4
x^2!=√0
x!=0
x∈R
-6*4x^2+3=0
Wy multiply elements
-24x^2+3=0
a = -24; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-24)·3
Δ = 288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{288}=\sqrt{144*2}=\sqrt{144}*\sqrt{2}=12\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{2}}{2*-24}=\frac{0-12\sqrt{2}}{-48} =-\frac{12\sqrt{2}}{-48} =-\frac{\sqrt{2}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{2}}{2*-24}=\frac{0+12\sqrt{2}}{-48} =\frac{12\sqrt{2}}{-48} =\frac{\sqrt{2}}{-4} $
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